-
Richard van der Hoff authored
The behaviour when casting from a uint32_t which has overflowed (so has the top bit set) to int32_t is implementation-defined, so let's avoid relying on it.
173cbe11
The behaviour when casting from a uint32_t which has overflowed (so has the top bit set) to int32_t is implementation-defined, so let's avoid relying on it.